Comments on: Python Url Encoding

By: Sven

Sven — Tue, 19 May 2009 21:02:03 +0000

Thanks for this code snippet. On my device a don’t have urllib, thus your approach saved my day

rgz — Mon, 18 May 2009 06:25:39 +0000

import urllib
urlencode = lambda s: urllib.urlencode({‘x’: s})[2:]
assert urlencode(“foo bar baz”) == “foo+bar+baz”

weber — Thu, 19 Mar 2009 18:50:55 +0000

urlib mothed as follows:

st = st.encode(�gb2312?)
m = {�par�:st,}
s = urllib.urlencode(m)
print s

Peter Wesselius — Thu, 09 Aug 2007 09:27:49 +0000

Your UrlEncode function can be refactored:

def UrlEncode(s):
r = ”
for c in s:
if c in HexCharacters:
o = ord(c)
r += ‘%’ + CleanCharHex(c)
else:
r += c
return r

Bas Westerbaan — Tue, 19 Jul 2005 11:51:41 +0000

Thanks! Seems I missed that one. I guess the name ‘quote’ was picked a bit awquardly.

Richard — Tue, 19 Jul 2005 10:46:29 +0000

Try the quote public method in the urllib module.